How can I know which radio button is selected via jQuery?How can I know which radio button is selected via jQuery? - Solution Checker - solutionschecker.com - Find the solution for any programming question. We as a solution checker will focus on finding the fastest possible solution for developers. Main topics like coding, learning.

I have two radio buttons and want to post the value of the selected one. How can I get the value with jQuery?

I can get all of them like this:

$("form :radio")

How do I know which one is selected?

Solution 1

To get the value of the selected radioName item of a form with id myForm:

$('input[name=radioName]:checked', '#myForm').val()

Here's an example:

$('#myForm input').on('change', function() {
  alert($('input[name=radioName]:checked', '#myForm').val());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
  <fieldset>
    <legend>Choose radioName</legend>
    <label><input type="radio" name="radioName" value="1" /> 1</label> <br />
    <label><input type="radio" name="radioName" value="2" /> 2</label> <br />
    <label><input type="radio" name="radioName" value="3" /> 3</label> <br />
  </fieldset>
</form>

Solution 2

Use this..

$("#myform input[type='radio']:checked").val();

Solution 3

If you already have a reference to a radio button group, for example:

var myRadio = $("input[name=myRadio]");

Use the filter() function, not find(). (find() is for locating child/descendant elements, whereas filter() searches top-level elements in your selection.)

var checkedValue = myRadio.filter(":checked").val();

Notes: This answer was originally correcting another answer that recommended using find(), which seems to have since been changed. find() could still be useful for the situation where you already had a reference to a container element, but not to the radio buttons, e.g.:

var form = $("#mainForm");
...
var checkedValue = form.find("input[name=myRadio]:checked").val();

Solution 4

This should work:

$("input[name='radioName']:checked").val()

Note the "" usaged around the input:checked and not '' like the Peter J's solution

Solution 5

You can use the :checked selector along with the radio selector.

 $("form:radio:checked").val();

Solution 6

If you want just the boolean value, i.e. if it's checked or not try this:

$("#Myradio").is(":checked")

Solution 7

Get all radios:

var radios = jQuery("input[type='radio']");

Filter to get the one thats checked

radios.filter(":checked")

Solution 8

Another option is:

$('input[name=radioName]:checked').val()

Solution 9

$("input:radio:checked").val();

Solution 10

In my case I have two radio buttons in one form and I wanted to know the status of each button. This below worked for me:

// get radio buttons value
console.log( "radio1: " +  $('input[id=radio1]:checked', '#toggle-form').val() );
console.log( "radio2: " +  $('input[id=radio2]:checked', '#toggle-form').val() );


    
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="toggle-form">
  <div id="radio">
    <input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">Plot single</label>
    <input type="radio" id="radio2" name="radio"/><label for="radio2">Plot all</label>
  </div>
</form>

Solution 11

Here's how I would write the form and handle the getting of the checked radio.

Using a form called myForm:

<form id='myForm'>
    <input type='radio' name='radio1' class='radio1' value='val1' />
    <input type='radio' name='radio1' class='radio1' value='val2' />
    ...
</form>

Get the value from the form:

$('#myForm .radio1:checked').val();

If you're not posting the form, I would simplify it further by using:

<input type='radio' class='radio1' value='val1' />
<input type='radio' class='radio1' value='val2' />

Then getting the checked value becomes:

    $('.radio1:checked').val();

Having a class name on the input allows me to easily style the inputs...

Solution 12

In a JSF generated radio button (using <h:selectOneRadio> tag), you can do this:

radiobuttonvalue = jQuery("input[name='form_id\:radiobutton_id']:checked").val();

where selectOneRadio ID is radiobutton_id and form ID is form_id.

Be sure to use name instead id, as indicated, because jQuery uses this attribute (name is generated automatically by JSF resembling control ID).

Solution 13

Also, check if the user does not select anything.

var radioanswer = 'none';
if ($('input[name=myRadio]:checked').val() != null) {           
   radioanswer = $('input[name=myRadio]:checked').val();
}

Solution 14

If you have Multiple radio buttons in single form then

var myRadio1 = $('input[name=radioButtonName1]');
var value1 = myRadio1.filter(':checked').val();

var myRadio2 = $('input[name=radioButtonName2]');
var value2 = myRadio2.filter(':checked').val();

This is working for me.

Solution 15

I wrote a jQuery plugin for setting and getting radio-button values. It also respects the "change" event on them.

(function ($) {

    function changeRadioButton(element, value) {
        var name = $(element).attr("name");
        $("[type=radio][name=" + name + "]:checked").removeAttr("checked");
        $("[type=radio][name=" + name + "][value=" + value + "]").attr("checked", "checked");
        $("[type=radio][name=" + name + "]:checked").change();
    }

    function getRadioButton(element) {
        var name = $(element).attr("name");
        return $("[type=radio][name=" + name + "]:checked").attr("value");
    }

    var originalVal = $.fn.val;
    $.fn.val = function(value) {

        //is it a radio button? treat it differently.
        if($(this).is("[type=radio]")) {

            if (typeof value != 'undefined') {

                //setter
                changeRadioButton(this, value);
                return $(this);

            } else {

                //getter
                return getRadioButton(this);

            }

        } else {

            //it wasn't a radio button - let's call the default val function.
            if (typeof value != 'undefined') {
                return originalVal.call(this, value);
            } else {
                return originalVal.call(this);
            }

        }
    };
})(jQuery);

Put the code anywhere to enable the addin. Then enjoy! It just overrides the default val function without breaking anything.

You can visit this jsFiddle to try it in action, and see how it works.

Fiddle

Solution 16

 $(".Stat").click(function () {
     var rdbVal1 = $("input[name$=S]:checked").val();
 }

Solution 17

This works fine

$('input[type="radio"][class="className"]:checked').val()

Working Demo

The :checked selector works for checkboxes, radio buttons, and select elements. For select elements only, use the :selected selector.

API for :checked Selector

Solution 18

try this one. it worked for me

$('input[type="radio"][name="name"]:checked').val();

Solution 19

To get the value of the selected radio that uses a class:

$('.class:checked').val()

Solution 20

I use this simple script

$('input[name="myRadio"]').on('change', function() {
  var radioValue = $('input[name="myRadio"]:checked').val();        
  alert(radioValue); 
});

Solution 21

Use this:

value = $('input[name=button-name]:checked').val();

Solution 22

DEMO : https://jsfiddle.net/ipsjolly/xygr065w/

	$(function(){
	    $("#submit").click(function(){      
	        alert($('input:radio:checked').val());
	    });
	 });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
       <tr>
         <td>Sales Promotion</td>
         <td><input type="radio" name="q12_3" value="1">1</td>
         <td><input type="radio" name="q12_3" value="2">2</td>
         <td><input type="radio" name="q12_3" value="3">3</td>
         <td><input type="radio" name="q12_3" value="4">4</td>
         <td><input type="radio" name="q12_3" value="5">5</td>
      </tr>
    </table>
<button id="submit">submit</button>

Solution 23

If you only have 1 set of radio buttons on 1 form, the jQuery code is as simple as this:

$( "input:checked" ).val()

Solution 24

I've released a library to help with this. Pulls all possible input values, actually, but also includes which radio button was checked. You can check it out at https://github.com/mazondo/formalizedata

It'll give you a js object of the answers, so a form like:

<form>
<input type="radio" name"favorite-color" value="blue" checked> Blue
<input type="radio" name="favorite-color" value="red"> Red
</form>

will give you:

$("form").formalizeData()
{
  "favorite-color" : "blue"
}

Solution 25

JQuery to get all the radio buttons in the form and the checked value.

$.each($("input[type='radio']").filter(":checked"), function () {
  console.log("Name:" + this.name);
  console.log("Value:" + $(this).val());
});

Solution 26

To retrieve all radio buttons values in JavaScript array use following jQuery code :

var values = jQuery('input:checkbox:checked.group1').map(function () {
    return this.value;
}).get();

Solution 27

try it-

var radioVal = $("#myform").find("input[type='radio']:checked").val();

console.log(radioVal);

Solution 28

Another way to get it:

 $("#myForm input[type=radio]").on("change",function(){
   if(this.checked) {
    alert(this.value);
    }
  });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
   <span><input type="radio" name="q12_3" value="1">1</span><br>
   <span><input type="radio" name="q12_3" value="2">2</span>
</form>

Solution 29

$(function () {
// Someone has clicked one of the radio buttons
var myform= 'form.myform';
$(myform).click(function () {
    var radValue= "";
    $(this).find('input[type=radio]:checked').each(function () {
        radValue= $(this).val();
    });
  })
});

Solution 30

Try

myForm.myOption.value