$('button').click(function () {
[1, 2, 3, 4, 5].forEach(function (n) {
if (n == 3) {
// it should break out here and doesn't alert anything after
return false
}
alert(n)
})
})<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Click me</button>My question: Why does it still alert next number although I call return? Just like: Ignore the code below and continue with next element
Solution 1
From the Mozilla Developer Network:
There is no way to stop or break a
forEach()loop other than by throwing an exception. If you need such behavior, theforEach()method is the wrong tool.Early termination may be accomplished with:
- A simple loop
- A
for...ofloopArray.prototype.every()Array.prototype.some()Array.prototype.find()Array.prototype.findIndex()The other Array methods:
every(),some(),find(), andfindIndex()test the array elements with a predicate returning a truthy value to determine if further iteration is required.
Solution 2
The return exits the current function, but the iterations keeps on, so you get the "next" item that skips the if and alerts the 4...
If you need to stop the looping, you should just use a plain for loop like so:
$('button').click(function () {
var arr = [1, 2, 3, 4, 5];
for(var i = 0; i < arr.length; i++) {
var n = arr[i];
if (n == 3) {
break;
}
alert(n);
})
})
You can read more about js break & continue here: http://www.w3schools.com/js/js_break.asp
